- 经验
- 57
- 分贝
- 0
- 家园分
- 0
- 在线时间:
- 0 小时
- 最后登录:
- 2005-12-28
- 帖子:
- 7
- 精华:
- 0
- 注册时间:
- 2005-8-16
- UID:
- 55128
注册:2005-8-16
|
发表于 2005-8-16 10:52:00
|显示全部楼层
各位大侠:
我在做S1240的自动开放,但脱机不正常.如果发0X18后交换机返回canceld,但再次联接需要等待很长时间.
我读到的交换机提示序列是:
0x0D, 0x0A, 0x11, 0x1B,
0x67, 0x1B, 0x5E, 0x11,
0x0D, 0x1B, 0x34, 0x1B,
0x54, 0x0C, 0x1b, 0x05, 0x0
我的初始化序列是:0x02, 0x45, 0x62, 0x45,
0x40, 0x40, 0x40, 0x20,
0x20, 0x20, 0x0d, 0x04, 0x0
;
我看到另外一个例子的初始化序列是:
init command AT&FX3S7=60&W */
buf[0] = 0x41;
buf[1] = 0x54;
buf[2] = 0x26;
buf[3] = 0x46;
buf[4] = 0x58;
buf[5] = 0x33;
buf[6] = 0x53;
buf[7] = 0x37;
buf[8] = 0x3d;
buf[9] = 0x36;
buf[10] = 0x30;
buf[11] = 0x26;
buf[12] = 0x57;
buf[13] = 0x0d;
脱机序列是:
buf[0] = 0x41;
buf[1] = 0x54;
buf[2] = 0x53;
buf[3] = 0x32;
buf[4] = 0x3d;
buf[5] = 0x30;
buf[6] = 0x34;
buf[7] = 0x33;
buf[8] = 0x3d;
我就想知道如果正确的联机,正确的脱机.
|
|